It's very intuitive to see, for example
6^3=216
6^2=36,
6^1=6,
and as you see why keep dividing by 6,
6^0=1
6^-1=1/6
6^-2=1/36
etc...
also, 6^n times 6^m=6^(m+n) right?
so 6^n*6^0=6^(n+0)=6^n, and this we see that 6^0 must be 1, and this argument is true all numbers (since my proof...