sighs.. I have to do 51 equations for chemistry lab!
But i'll pick some and show ya..
Just wondering if these are right!.. Sorry if i cant make lower case of numbers.. but u can understand the concepts..
If i do anything wrong.. show me what I did wrong and why?
thanks!
(a) + (b) =
a = NH3 (aq) b= BaCl2(aq)
Molecular Equation:
NH3(aq) + BaCl2(aq) → BaH3(aq) + NCl2(aq)
Ionic Equation:
N3+(aq)+ 3H-(aq) + Ba2+(aq) + 2Cl-(aq) → Ba2+(aq) + 3H-(aq) + N3+(aq) + 2Cl-(aq)
Net Ionic Equation:
N/A
No Reaction
(a) + (c) =
a = NH3 c = CoCl2
Molecular Equation:
NH3(aq) + CoCl2(aq) → CoH3(aq) + NCl2(aq)
Ionic Equation:
N3+(aq) + 3H-(aq) + Co2+(aq) + 2Cl-(aq) → Co3+(aq) + 3H-(aq) + N3+(aq) + 2Cl-(aq)
Net Ionic Equation:
Co2+ → Co3+
(a) + (d) =
a = NH3 d = CuSo4
Molecular Equation:
NH3(aq) + CuSo4(aq) → CuH3(aq) + NSo4(aq)
Ionic Equation:
N3+(aq) + 3H-(aq) + Cu4+(aq) + So4-(aq) → Cu3+(aq)+3H-(aq) + N3+(aq) + So4-(aq)
Net Ionic Equation:
Cu4+ → Cu3+
But i'll pick some and show ya..
Just wondering if these are right!.. Sorry if i cant make lower case of numbers.. but u can understand the concepts..
If i do anything wrong.. show me what I did wrong and why?
thanks!
(a) + (b) =
a = NH3 (aq) b= BaCl2(aq)
Molecular Equation:
NH3(aq) + BaCl2(aq) → BaH3(aq) + NCl2(aq)
Ionic Equation:
N3+(aq)+ 3H-(aq) + Ba2+(aq) + 2Cl-(aq) → Ba2+(aq) + 3H-(aq) + N3+(aq) + 2Cl-(aq)
Net Ionic Equation:
N/A
No Reaction
(a) + (c) =
a = NH3 c = CoCl2
Molecular Equation:
NH3(aq) + CoCl2(aq) → CoH3(aq) + NCl2(aq)
Ionic Equation:
N3+(aq) + 3H-(aq) + Co2+(aq) + 2Cl-(aq) → Co3+(aq) + 3H-(aq) + N3+(aq) + 2Cl-(aq)
Net Ionic Equation:
Co2+ → Co3+
(a) + (d) =
a = NH3 d = CuSo4
Molecular Equation:
NH3(aq) + CuSo4(aq) → CuH3(aq) + NSo4(aq)
Ionic Equation:
N3+(aq) + 3H-(aq) + Cu4+(aq) + So4-(aq) → Cu3+(aq)+3H-(aq) + N3+(aq) + So4-(aq)
Net Ionic Equation:
Cu4+ → Cu3+